Monday, June 19, 2017

Formula 1

Ekadhikena Purvena (एकाधिकेन पूर्वेण)
The Sutra means: “By one more than the previous one”.
पहले से एक अधिक के द्वारा।
1. This sutra is useful to the ‘squaring of numbers ending in 5’.
Example252.
For the number 25, the last digit is 5 and the 'previous' digit is 2. According to formula 'One more than the previous one', that is, 2+1=3. The Sutra gives the procedure 'to multiply the previous digit 2 (by one more than itself) by 3. It becomes the L.H.S (left hand side) of the result, that is, 2 X 3 = 6. The R.H.S (right hand side) of the result is 52, that is, 25.
252 = 2 X 3 / 25 = 6/25=625.
152 = 1 X (1+1) /25 =225;
952 = 9 X 10/25 = 9025;
135= 13 X 14/25 = 18225;

2. Vulgar fractions whose denominators are numbers ending in Nine
We take examples of 1 / a9, where a = 1, 2………… In the conversion of vulgar fractions into recurring decimals, Ekadhika process can be effectively used both in division and multiplication.

Division Method:  Value of 1 / 19.
The numbers of decimal places before repetition is the difference of numerator and denominator, 19 -1=18 places. For the denominator 19, the purva (previous) is 1. Hence Ekadhikena purva (one more than the previous) is 1 + 1 = 2.
1.      0.10 (Divide numerator 1 by 20, 0 times, 1 remainder)
2.      0.005 (Divide 10 by 2, 5 times, No remainder)
3.      0.0512 (Divide 5 by 2, 2 times, 1 remainder)
4.      0.0526 (Divide 12 or12 by 2, 6 times, No remainder)
5.      0.05263 (Divide 6 by 2, 3 times, No remainder)
6.      0.0526311(Divide 3 by 2, 1 time, 1 remainder)
7.      0.05263115 (Divide 11 or 11 by 25 times, 1 remainder)
8.      0.052631517 (Divide 15 or 15 by 2, 7 times, 1 remainder)
9.      0.0526315718 (Divide 17 or 17 by 2, 8 times, 1 remainder)
10.       0.0526315789 (Divide 18 or 18 by 2, 9 times, No remainder)
11.       0.052631578914 (Divide 9 by 2, 4 times, 1 remainder)
12.       0.052631578947 (Divide 14 or 14 by 2, 7 times, No remainder)
13.       0.05263157894713 (Divide 7 by 2, 3 times, 1 remainder)
14.       0.052631578947316 (Divide 13 or 13 by 2, 6 times, 1 remainder)
15.       0.052631578947368 (Divide 16 or 16 by 2, 8 times, No remainder)
16.       0.0526315789473684 (Divide 8 by 2, 4 times, No remainder)
17.       0.05263157894736842 (Divide 4 by 2, 2 times, No remainder)
18.       0.052631578947368421 (Divide 2 by 2, 1 time, No remainder)
0 

Multiplication Method: Value of 1 / 19
For 1 / 19, 'previous' of 19 is 1. And one more than of it, is 1 + 1 = 2. Therefore 2 is the multiplier for the conversion. We write the last digit in the numerator (अंश) as 1 and follow the steps leftwards.
1.      1
2.      21(multiply 1 by 2, put to left)
3.      421(multiply 2 by 2, put to left)
4.      8421(multiply 4 by 2, put to left)
5.      168421 (multiply 8 by 2=16, 1 carried over, 6 put to left)
6.      1368421 (6 X 2 =12, +1 = 13, 1 carried over, 3 put to left)
7.      7368421 (3 X 2, = 6 +1 = 7, put to left)
8.      147368421 (7 X 2 =14, 1 carried over, 4 put to left)
9.      947368421 (4 X 2, = 8, +1 = 9, put to left)
10.       18947368421(9 X 2 =18, 1 carried over, 8 put to left)
11.       178947368421(8 X 2 =16,+1=17, 1 carried over, 7 put to left)
12.       1578947368421(7 X 2 =14,+1=15, 1 carried over, 5 put to left)
13.       11578947368421(5 X 2 =10,+1=11,1 carried over, 1 put to left)
14.       31578947368421(1 X 2 =2,+1=3, 3 put to left)
15.       631578947368421(3 X 2 =6, 6 put to left)
16.       12631578947368421(6 X 2 =12, 1 carried over, 2 put to left)
17.       52631578947368421(2 X 2 =4,+1=5, 5 put to left)
18.       1052631578947368421(5 X 2 =10, 1 carried over, 0 put to left)
Now from step 18 onwards the same numbers and order towards left continue.
Thus 1 / 19 = 0.052631578947368421

Example: Value of 1 / 7.
1/7 में हर के अंक को बनाने के लिए हर और अंश में से गुणा करते हैं।
(1/7 = 7/49); हर के 49 का पूर्वेण हैं, 4; जिसका एकाधिक हैं। भिन्न के आवृति दशमलव स्वरूप का अन्तिम अंक 7 होगा तथा 7-1 = अंकों के पश्चात् दशमलव अंकों की पुनरावृति होगी।
1.      7
2.      357 (multiply 7 by 5 =35, 3 carried over, 5 put to left)
3.      2857 (5 X 5 =25, +3 = 28, 2 carried over, 8 put to left)
4.      42857 (8 X 5 =40, +2 = 42, 4 carried over, 2 put to left)
5.      142857 (2 X 5 =10, +4 = 14, 1 carried over, 4 put to left)
6.      2142857 (4 X 5 =20, +1 = 21, 2 carried over, 1 put to left)
अतः

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